Question

the numerator of a fraction is 3 less than the denominator. if both the numerator and denominator are increased by 2, the new fraction becomes 6/7.Find the original fraction

Answer 1

let the fraction=a/b=b-3/b
ATQ,
b-3+2/b+2=6/7
7[b-3+2]=6[b+2]
7b-21+14=6b+12
7b-6b=12+21-14
b=
the original fraction=b-3/b=19-3/19
16/19

Answer 2

Hiii friend,

Let the Denominator of the fraction be X.

Then the numerator of the fraction = (X-3)

Fraction = Numerator/Denominator = (X-3)/X.

Numerator and denominator both are increased by 2 then the Numerator and denominator become. (X+2) and (X-3+2) = (X-1).

Therefore,

Fraction = Numerator/Denominator = (X-1)/X+2.

6/7 = X-1/X+2

6(X+2) = 7(X-1)

6X +12 = 7X-7

7X-6X = 12+7

X = 19

Therefore,


Denominator = X = 19

And,

Numerator = (X-3) = (19-3) = 16

Fraction = Numerator/Denominator = (X-3)/X = 16/19.


HOPE IT WILL HELP YOU.... :-)