Question

the numerator of a fraction is 3 less than the denominator. if both the numerator and denominator are increased by 2,the new fraction becomes 6/7.Find the original fraction

Answer 1

Let the denominator be x,

Nominator be x-3

Fraction -
$\frac{x - 3}{x}$

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ATQ,

$\frac{x - 3 + 2}{x + 2} = \frac{6}{7}$

7(x-1)= 6(x+2)

7x -7 = 6x+12

7x-6x = 12+7

x = 19

Fraction -

$\frac{x - 4}{x} = \frac{19 - 3}{19} = \frac{16}{19}$

I hope this will help you

-by ABHAY

Answer 2

Hiii friend,

Let the denominator of the fraction be X.

Then the numerator of the fraction = (X-3)

Fraction = Numerator/Denominator = X-3/X.

Numerator and denominator are increased by 2 then the Numerator and denominator becomes (X-3+2) and (X+2).

Fraction = Numerator/Denominator =(X-3+2)/(X+2).



According to question,

(X-3+2)/(X+2) = 6/7

X-1/X+2 = 6/7

7(X-1) = 6(X+2)

7X-7 = 6X+12

7X-6X= 12+7

X = 19

Numerator = (X-3) = (19-3) = 16

And,

Denominator =(X) = 19


Therefore,

Original Fraction = Numerator/Denominator = (X-3)/X= 19/16


HOPE IT WILL HELP YOU.... :-)