The numerator of a fraction is 3 less than the denominator
If both the numerator and denominator are incerased by 2,
the next feaction becomes 6/7 find the original number
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Step-by-step explanation:
Hiii friend,
Let the denominator of the fraction be X.
Then the numerator of the fraction = (X-3)
Fraction = Numerator/Denominator = X-3/ X.
Numerator and denominator are increased by 2 then the Numerator and denominator becomes (X-3+2) and (x+2).
Fraction = Numerator/Denominator =(X-3+2)/(x+2).
According to question,
(X-3+2)/(x+2) = 6/7
X-1/X+2 = 6/7
7(X-1) = 6(X+2)
7X-7 = 6X+12
7X-6X=12+7
X = 19
Numerator = (X-3) =(19-3) = 16
And,
Denominator =(X) = 19
Therefore,
Original Fraction = Numerator/ Denominator = (X-3)/X=19/16
HOPE IT WILL HELP YOU.... :-)
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