The numerator of a fraction is 3 less than the denominator if 2 is added in the denominator and numerator is decreased by 5 the fraction becomes 28/33
Answers
let the denominator of a fraction be x
∴numerator of a fraction will be [ x-3]
∴ the fraction will be [ x-3] /x
ATP
if 2 is added in the denominator and 5 is subtracted from the numerato we get
⇒ [x-3-5] /x+2 =28/33
⇒ [x- 8] /x+2 =28/33
⇒33 *[x-8] =[x+2 ]*28
⇒33x-264 =28x+56
⇒5x =320
⇒x =64 .....................................denominator of a fraction
⇒ [ x-3] =[64-3]=61 .......................numerator of a fraction
∴ the fraction is 61/64 ANS
let the denominator be x
∴numerator will become [ x-3]
∴ the fraction = x-3 /x
BTQ
2 is added in the denominator and 5 is decreased in numerato
or x-3-5 /x+2 =28/33
or x- 8 /x+2 =28/33
or 33 *[x-8] =[x+2 ]*28
or 33x-264 =28x+56
or x =64 is denominator
or [ x-3] =[64-3]=61 is numerator
-> the fraction is 61/64 ans