The numerator of a fraction is 3 less than the denominator. If 2 is added to both the numerator and the denominator, then the sum of the new fraction and the original fraction is . Find the original fraction.
Answers
SOLUTION :
Let x be the denominator of a original fraction.
Then, Numerator be (x - 3)
Original Fraction = Numerator/ denominator = (x - 3)/x
New fraction = (x - 3 + 2)/(x + 2) = (x - 1)/(x + 2)
[When 2 is added to numerator and denominator]
New fraction = (x - 1)/(x + 2)
A.T.Q
(x - 3)/x + (x - 1)/(x + 2) = 29/20
[ (x - 3)(x + 2) + x(x -1)] / x(x + 2) = 29/20
[By taking LCM]
[(x² - 6 - x + x² - x)] / x² + 2x = 29/20
20(2x² - 2x - 6) = 29(x² + 2x)
[By cross multiplication]
40x² - 120 - 40x = 29x² + 58x
40x² - 29x² - 40x - 58x - 120 = 0
11x² - 98x - 120 = 0
11x² - 110x + 12x -120 = 0
[By middle term splitting]
(11x + 12)(x - 10) = 0
(11x + 12) = 0 or (x - 10) = 0
11x = - 12 or x = 10
x = -12/11 or x = 10
Since, x is a natural number , so x ≠ - 12/11
Therefore, x = 10
Numerator = (x - 3) = 10 - 3 = 7/10
Original Fraction = (x - 3)/x = (10 - 3)/10 = 7/10
Hence, the original fraction is 7/10.
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