Question

the numerator of a fraction is 3 less than the denominator if both the numerator and denominator are increased by 2 the new fraction becomes 1 by 7 find the original fraction​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Solution:

Let the denominator = x

numerator = x-3

fraction = (x-3)/x

If both the numerator and

denominator are increased by 2

the new fraction becomes 1/7

=> (x-3+2)/(x+2) = 1/7

=> (x-1)/(x+2) = 1/7

Do the cross multiplication, we get

=> 7(x-1) = (x+2)

=> 7x - 7 = x + 2

=> 7x - x = 2+7

=> 6x = 9

=> x = 9/6

=> x = 3/2 = 1.5

Therefore ,

Original fraction = (x-3)/x

= (1.5-3)/1.5

= (-1.5)/1.5

= -1

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