Question

The numerator of a fraction is 3 less then it's denominator if we need 1 to both numerator and denominator it becomes equal. Find the fraction

Answer 1

Answer:

The numerator of a fraction is 3 less than its denominator.

n = d - 3

:

if we add 1 to both numerator and denominator it becomes equal to 2/3.

Cross multiply

3(n+1) = 2(d+1)

3n + 3 = 2d + 2

3n = 2d + 2 - 3

3n = 2d - 1

replace n with (d-3), from the 1st equation

 

3(d-3) = 2d - 1

3d - 9 = 2d - 1

3d - 2d = -1 + 9

d = 8

then

n = 8 - 3

n = 5

therefore

fraction = 2/5

You can check this for yourself, add 1 to the numerator and denominator

Answer 2

Answer:

Ans is ⅝

Step-by-step explanation:

Answer:

The fraction is \frac{5}{8}

8

5

Step-by-step explanation:

Let the numerator be N and denominator be D

So, the required fraction will be \frac{N}{D}

D

N

According to question,

The numerator of a fraction is 3 less than denominator, that is ,

N = D - 3

So, the new fraction is \frac{D-3}{D}

D

D−3

Also, it is given that if 1 is added to both its numerator and denominator it becomes 2 / 3

Therefore now,

\frac{D-3+1}{D+1} = ⅔

D+1

D−3+1

=

3

2

\frac{D-2}{D+1} = \frac{2}{3}

D+1

D−2

=

3

2

3 ( D - 2 ) = 2 ( D + 1 )

3 D - 6 = 2 D + 2

3 D - 2 D = 2 + 6

D = 8

We know,

N = D - 3

N = 8 - 3 = 5

So the fraction

N

----

D

⅝

Hence,

The fraction is ⅝

Hope it helps ! ❤️