Question

The numerator of a fraction is 4 less than its denominator. If 3 added to both the numerator and the denominator the resulting number is 3/4. What is the original fraction

Answer 1

Answer:

Let X denominator

1. So fraction is (X-4) /X

2. 3 is added to both numerator and denominator, 3/4 is the resulting number

    (X-4+3) / (X+3) = 3/4

(X-1) / (X+3) = 3/4

3. Operation,

    4(X-1) = 3(X+3)

    4X-4 = 3X + 9

           X = 9+4 = 13

4. So 13-4 / 13 = 9/13

5. 9/13 is the original fraction.

Step-by-step explanation:

Answer 2

Answer:

The Numerator would then be 9/13.

Step-by-step explanation:

Assume that "x" was the initial fraction's remainder. The numerator of the fraction would be "x-4" according to the issue as presented.

The issue now says that if 3 is added to the initial fraction's numerator and denominator, the resulting fraction will be 3/4. The new percentage would be as follows:

(x-4+3) / (x+3) = 3/4

When we simplify the previous solution, we get:

(x-1) / (x+3) = 3/4

By increasing the solution by two, we obtain:

4(x-1) = 3(x+3)

To solve for "x," we obtain:

4x - 4 = 3x + 9

x = 13

Consequently, 13 is the initial fraction's remainder. Furthermore, the numerator would be 4 less than the divisor, which would be 13-4=9, according to the issue.

The Numerator would then be 9/13.

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