The numerator of a fraction is 4 less than its denominator. If the numerator is decreased by 2 and denominator is increased by 1, then the fraction becomes Find the fraction in thed
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Answers
Answer:
Let’s assume the numerator of the fraction to be x and the denominator of the fraction to be y.
So, the required fraction is x/ y
From the question it’s given as,
The numerator of the fraction is 4 less the denominator.
Thus, the equation so formed is
, x = y – 4
⇒ x – y = −4 …… (i)
And also it’s given in the question as,
If the numerator is decreased by 2 and denominator is increased by 1, then the denominator is 8 times the numerator.
Putting the above condition in an equation,
we get
y + 1 = 8(x-2)
⇒ y + 1 = 8x – 16
⇒ 8x – y = 1 + 16
⇒ 8x – y = 17 …… (ii) Solving (i) and (ii), Subtracting the equation (ii) from (i),
we get
(x – y) – (8x – y) = – 4 – 17
⇒ x – y − 8x + y = −21
⇒ −7x = −21
⇒ x = 21 /7
⇒ x = 3
Substituting the value of x = 3 in the equation (i),
we find y
3 – y = – 4
⇒ y = 3 + 4
⇒ y = 7
Therefore, the fraction is 3/ 7
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