Question

The numerator of a fraction is 4 less than the denominator. If I is added to both its
numerator and denominator, it becomes 1/2
Find the fraction.​

Answer 1

Step-by-step explanation:

Let the denominator be x

Numerator = x-4

x-4/x

If one is added to both of them

x-4+1/x+1=1/2

x-3/x+1=1/2

=2x-6=x+1

2x-x=1+6

x=7

The denominator is 7

The numerator = 7-4=3

The number is 3/7

Answer 2

Step-by-step explanation:

$let \: the \: numerator \: of \: the \: required \: fraction \: be \: x$

$then \: its \: numerator = (x - 4)$

$∴ \: \frac{x - 3 \: + 1}{x - 1} \: = \: \frac{1}{2}$

$= > \: \frac{x - 3}{x + 1} \: = \: \frac{1}{2} \: = > \: 2(x - 3) = x + 1$

$= > \: 2x \: - 6 = x + 1 = > \: 2x \: - x \: = 6 + 1 \: = > x = 7$

$∴ \: denominator \: = \: 7 \: and \: numerator \: = \: (7 - 4) = 3$

$hence \: the \: required \: fraction \: is \: \frac{3}{7}$

I hope it helped u...