Question

the numerator of a fraction is 4 less than the denominator if 1 is added to both its numerator and denominator it became ½ to find a fraction

Answer 1

Let the denominator of the fraction be $x$. 
Then, the numerator of the fraction is $x-4$. 
Now, we know that the fraction is $\frac{x-4}{x}$
We have to create an equation and find the value of $x$. 

$\frac{(x-4)+1}{x+1} = \frac{1}{2}$
$\frac{x-4+1}{x+1} = \frac{1}{2}$
$\frac{x-3}{x+1} = \frac{1}{2}$
I am going to use cross multiplication method. 
$2(x-3) = 1(x+1)$
$2x-6 = x+1$
$2x-x = 1+6$
$x = 7$

We have found the value of x to be 7. 
Numerator = 

Answer 2

Answer:

Step-by-step explanation:

Let the denominator be x

and the numerator be x-4

X-4 +1/ X+1 = 1/2

2(X-4+1) = X+1

2x -8 +2 =  X+1

2x -x = 1+8-2

x = 7

Therefore, fraction = x-4 / x

                                = 7-4 / 7

                                 = 3 / 7 ans.