the numerator of a fraction is 4 less than the denominator ,if both the numerator and denominator are increased by 1 the value of the fraction is 2/3, find the fraction
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let the fraction be x / y
given ,
x = y - 4 ------------- -eq.(1)
y - 4 + 1 / y + 1 = 2 / 3
( y - 3 ) / y + 1 = 2 / 3
3 (y - 3 )= 2( y + 1)
3y - 9 = 2y + 2
3y- 2y = 11
y = 11
put value of "y in (1) ,we get
x = 7
hence,fraction, x / y = 7 / 11
hope it helps
given ,
x = y - 4 ------------- -eq.(1)
y - 4 + 1 / y + 1 = 2 / 3
( y - 3 ) / y + 1 = 2 / 3
3 (y - 3 )= 2( y + 1)
3y - 9 = 2y + 2
3y- 2y = 11
y = 11
put value of "y in (1) ,we get
x = 7
hence,fraction, x / y = 7 / 11
hope it helps
Answered by
0
Let the denominator be x The numerator will then be x-4 The fraction is now x-4/x On adding 1 to both numerator and denominator, the fraction is x-4+1/x+1=2/3 x-3/x-4=2/3 On cross multiplying, 3(x-3)=2(x+1) 3x-9=2x+2 3x-2x=2+9 x=11 <hope it helps! >
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