Question

the numerator of a fraction is 4 less that it's denominator. if 1 is added to both its numerator and denominator, it becomes ⁴/¹². Fiund the fraction!!
help please!!​

Answer 1

Question : –

The numerator of a fraction is 4 less than it's denominator. If 1 is added to both it's numerator and Denominator. Then, it becomes 4/12. Find the fraction.

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★ Let the Denominator of the fraction be x respectively.

$Then, \: it's Numerator = (x \: – \: 4).$

$According \: to \: the \: Question \rightarrow$

• If 1 is added to both it's numerator and Denominator. Then, it becomes 4/12.

$⟹ \: \frac{(x - 4) + 1}{x + 1} = \frac{4}{12}$

$⟹ \: \frac{x - 3}{x + 1} = \frac{4}{12}$

$⟹12(x - 3) = 4(x + 1)$

$⟹12x - 36 = 4 x + 4$

$⟹12x - 4x = 4 + 36$

$⟹8x = 40$

$⟹x = \frac{40}{8}$

$\color{red}⟹x = 5$

so,

Numerator of fraction, (x – 4) = (5 – 4) = 1

Denominator of fraction, x = 5

★ hence the required fraction is 1/5...

Answer 2

Question : –

The numerator of a fraction is 4 less than it's denominator. If 1 is added to both it's numerator and Denominator. Then, it becomes 4/12. Find the fraction.

_____________________________

★ Let the Denominator of the fraction be x respectively.

According to the Question ⟹

If 1 is added to both it's numerator and Denominator. Then, it becomes 4/12.

⟹ (x - 4) + 1 {x + 1} = 4/12

⟹ {x - 3} {x + 1} = 4/12

⟹12(x - 3) = 4(x + 1)

⟹12x - 36 = 4 x + 4

⟹12x - 4x = 4 + 36

⟹8x = 40

⟹x = 40/8

⟹x = 5

So ,

⟹ Numerator of fraction , (x – 4) = (5 – 4) = 1

⟹ Denominator of fraction , x = 5

★ Hence the required fraction is 1/5...