Question

the numerator of a fraction is 5 less than the denominator if 5 added to numerator and 2 to the denominator , fraction becomes 4/5 find. the frictional.​

Answer 1

Answer:

ಜಿ ಸೇ ಜಿಂಕೆ ಎಂಟು ಇಂಜಿನೀಯರಿಂಗ್ ಔಙ ಇಂಥ ಗೇ ಇಂಥ ಎಂಟು ಇಂಚು ಬಂತು ಆಠಠಛ ಎಂಟು ಇಂಜಿನೀಯರಿಂಗ್ ಒಙ

Answer 2

Answer :

The fraction is $\sf \to \dfrac{3}{8}$

Step-by-step explanation :

Question says that, a fraction where the numerator is 5 less than the denominator.

If 5 added to the numerator and 2 to the denominator the fraction becomes $\sf \dfrac{4}{5}$

Find the fraction.

Step 1 : Let's assume :

The denominator : $x$

So, the numerator will be : $(x - 5)$

Step 2 : 5 added to the numerator :

5 added to the numerator :

$\to (x - 5) + 5$

$\to x - 5 + 5$

$\to x$

And also, 2 added to the denominator :

$\to (x + 2)$

Step 3 : Solving for $x$ :

${\underline{\boldsymbol{According \: to \: the \: question :}}}$

$\implies \dfrac{x}{x + 2} = \dfrac{4}{5}$

$\implies 5x = 4(x + 2)$

$\implies 5x = 4x + 8$

$\implies 5x - 4x = 8$

$\implies x = 8$

$\sf\therefore The \: denominator \: is \bf\: 8$

Hence, the numerator will be :

→ 5 less than the denominator

Or,

→ 8 - 5 = 3.

The fraction is :

$\sf \to\dfrac{Numerator}{Denominator}$

$\sf \to \dfrac{3}{8}$

_____________________

Verification :

If 5 is added to the numerator i.e., 3 and 2 to the denominator the fraction becomes $\dfrac{4}{5}$

Lets check :

$\sf \to \dfrac{3 + 5}{8 + 2}$

$\sf \to \dfrac{8}{10}$

$\sf \to \dfrac{4}{5}$

Hence, verified