The numerator of a fraction is 6 less than the denominator if 3 is added to the numerator, the fraction becomes 2/3 find the original fraction
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let the denominator be x
then, numerator = x-6
according to question ,
=> (x-6)+3/x = 2/3
=> (x-6+3)/x = 2/3
=> (x-3)/x = 2/3
=> 3(x-3) = 2x
=> 3x-9 = 2x
=> 3x-2x = 9
=> x = 9. (denominator)
numerator = x-6 => 9-6 = 3
then , fraction = 3/9
hope this helps
then, numerator = x-6
according to question ,
=> (x-6)+3/x = 2/3
=> (x-6+3)/x = 2/3
=> (x-3)/x = 2/3
=> 3(x-3) = 2x
=> 3x-9 = 2x
=> 3x-2x = 9
=> x = 9. (denominator)
numerator = x-6 => 9-6 = 3
then , fraction = 3/9
hope this helps
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