the numerator of a fraction is 6 less than the denominator. if 3 is added to the numerator the fraction becomes equal to 2/3 find the original fraction
Answers
Answered by
26
Heya friend,
------------------------------------------------------------
Let the denominator of the fraction be x. Then,
Numerator = x - 6
New numerator formed = x - 6 + 3
= x - 3
According to question,
x - 3/x = 2/3
=> 3(x - 3) = 2x
=> 3x - 9 = 2x
=> 3x - 2x = 9
=> x = 9
Hence, the denominator of the fraction is 9.
Numerator of the fraction = 9 - 6 = 3.
So, the original fraction = 3/9.
Thanks
With regards@
Tanisha
------------------------------------------------------------
Let the denominator of the fraction be x. Then,
Numerator = x - 6
New numerator formed = x - 6 + 3
= x - 3
According to question,
x - 3/x = 2/3
=> 3(x - 3) = 2x
=> 3x - 9 = 2x
=> 3x - 2x = 9
=> x = 9
Hence, the denominator of the fraction is 9.
Numerator of the fraction = 9 - 6 = 3.
So, the original fraction = 3/9.
Thanks
With regards@
Tanisha
Answered by
1
Let the numerator be x
& denominator be y
according to the question,
x=y-6......i
in case second,
x+3/y=2/3
3x-2y=9.....ii
putting the value of x in the equation ii
3x-2y=9
3(y-6)-2y=9
3y-18-2y=9
y-18=9
y=9+18
y=27
putting value of y in equation i
x=y-6
x=27-6
x=21
the required fraction is 21/27
=7/9
hope this helps you....☺
& denominator be y
according to the question,
x=y-6......i
in case second,
x+3/y=2/3
3x-2y=9.....ii
putting the value of x in the equation ii
3x-2y=9
3(y-6)-2y=9
3y-18-2y=9
y-18=9
y=9+18
y=27
putting value of y in equation i
x=y-6
x=27-6
x=21
the required fraction is 21/27
=7/9
hope this helps you....☺
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