Question

The numerator of a fraction is 7 less than the denominator. If two is added to both numerator and denominator, then it becomes 3/10. Find the original fraction. (By taking variable, not a direct answer) Pls tell

Answer 1

Answer:

x-5 / x+2 = 3x+6

10x-50=3x+6

7x=56

x=8

answer= 8

Step-by-step explanation:

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Answer 2

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▪ Given :-

• The numerator of a fraction is 7 less than the denominator.

• If two is added to both numerator and denominator, then it becomes 3/10.

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▪ To Find :-

• The Original Fraction

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▪ Solution :-

Let Numerator and Denominator of Original Fraction be :

• Numerator = x

Accordingly :

• Denominator should be = x + 7

So ,

Original Fraction is : $\large \mathtt{\dfrac{x}{ x + 7} }$

$\large \bigstar \: \underline{ \pmb{ \mathfrak{ \text{A}fter \: \text{A}dding\: 2 \: to \: Each: }}}$

Fraction Becomes : $\mathtt{ \dfrac{x + 2}{x + 9} }$

$\large \bigstar \: \underline{ \pmb{ \mathfrak{ \text{A}ccording \: to \: the \: Given \: Condition }}}$

$\mathtt{ \dfrac{x + 2}{x + 9} } = \frac{3}{10} \\ \\ \large : \longmapsto \mathtt{10(x + 2) = 3(x + 9) } \\ \\ \large : \longmapsto \mathtt{10x + 20 = 3x + 27 } \\ \\ \Large : \longmapsto \mathtt{7x = 7} \\ \\ \LARGE\purple{ :\longmapsto \underline {\boxed{{\bf x = 1} }}}$

Hence ,

Original Fraction is : $\large \mathtt{\dfrac{1}{ 1+7}}$

That Is :

$\Large\pink{\maltese \:\:\underline{\mathfrak{Original\:\:Fraction=\dfrac{1}{8}}}}$

$\Large \red{\mathfrak{  \text{W}hich \:   \: is  \:  \: the  \:  \: required} }\\ \huge \red{\mathfrak{ \text{ A}nswer.}}$

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