Math, asked by ramagopalarishik, 20 days ago

The numerator of a fraction is 8 less than the denominator. If the numerator is increased by 17 and the denominator is decreased by 1, the new fraction obtained is 32. Find the fraction.

Answers

Answered by thanmaiakula1
0

Answer:

Option (b) 79.2 cm² is the required area of ∆ ABC .

Step-by-step explanation:

According to the Question

It is given that,

Base of Triangle ,b = 22cm

Height of triangle ,h = 7.2 cm

we have to calculate the area of given triangle .

The area of triangle is calculated by

Area of Triangle = 1/2 × base × height

by putting the value we get

→ Area of ∆ABC = 1/2 × 22 × 7.2

→ Area of ∆ABC = 11 × 7.2

→ Area of ∆ABC = 79.2 cm²

Hence, the area of ∆ABC is 79.2 cm².

Option (b) 79.2 cm² is the required answer .

Additional Information !!

\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}

FormulasofAreas:−

⋆Square=(side)

2

⋆Rectangle=Length×Breadth

⋆Triangle=

2

1

×Breadth×Height

⋆Scalene△=

s(s−a)(s−b)(s−c)

⋆Rhombus=

2

1

×d

1

×d

2

⋆Rhombus=

2

1

d

4a

2

−d

2

⋆Parallelogram=Breadth×Height

⋆Trapezium=

2

1

(a+b)×Height

⋆EquilateralTriangle=

4

3

(side)

2

Similar questions