the numerator of a fraction is less than its denominator by 1 if the numerator becomes three times and the denominator is increased by 19. the new fraction becomes 1/7 find the fraction
Answers
Step-by-step explanation:
Given :-
The numerator of a fraction is less than its denominator by 1 if the numerator becomes three times and the denominator is increased by 19. the new fraction becomes 1/7.
To find :-
Find the fraction ?
Solution :-
Let the denominator be X
Then the numerator = Denominator -1
=> The numerator = X-1
Then the fraction = (X-1)/X
If the numerator becomes three times then it will be 3(X-1)
Then the denominator is Increased by 19
=> (X+19)
Then new fraction = 3(X-1)/(X+19)
According to the given problem
The new fraction = 1/7
=> 3(X-1)/(X+19) = 1/7
On applying cross multiplication then
=> 3(X-1)×7 = (X+19)
=> 21(X-1) = X+19
=> 21X-21 = X+19
=> 21X-X = 19+21
=> 20X = 40
=> X = 40/20
=> X = 2
Denominator = 2
Numerator = 2-1 = 1
Fraction = 1/2
Answer:-
The required fraction for the given problem is 1/2
Check :-
The fraction = 1/2
Numerator = 1 = 2-1
=> Denominator -1
And
3 times the numerator = 3(1) = 3
Denominator+19 = 2+19 = 21
New fraction = 3/21 = 1/7
Verified the given relations in the given problem
Used formulae:-
Fraction = Numerator / Denominator
QUESTION:-
the numerator of a fraction is less than its denominator by 1 if the numerator becomes three times and the denominator is increased by 19. the new fraction becomes 1/7 find the fraction ?
Given:-
- the numerator of a fraction is less than its denominator by 1
- if the numerator becomes three times and the denominator is increased by 19. the new fraction becomes 1/7
TO FIND:-
The fraction