Math, asked by SiddhiSalve, 9 months ago

the numerator of a fraction is less than the denominator. if 1 added to the denominator it becomes 1/2 find the fraction​

Answers

Answered by ghourimohammed6423
1

Answer:

Let the numerator be x

Therefore, denominator is x+2

The fraction is  

x+2

x

​  

 

Now,    

x+2

x

​  

+  

x+3

x+1

​  

=  

15

19

​  

 

=>  

(x+2)(x+3)

x  

2

+3x+(x+1)(x+2)

​  

=  

15

19

​  

 

=>  

(x+2)(x+3)

x  

2

+3x+x  

2

+3x+2

​  

=  

15

19

​  

 

=>15(x  

2

+3x+x  

2

+3x+2)=19(x+2)(x+3)

=>15(2x  

2

+6x+2)=19(x  

2

+5x+6)

=>30x  

2

+90x+30=19x  

2

+95x+114

=>11x  

2

−5x−84=0

=>11x  

2

−33x+28x−84=0

=>11x(x−3)+28(x−3)=0

=>(11x+28)(x−3)=0

Therefore, x=3 or x=−  

11

28

​  

 

For x=−  

11

28

​  

, denominator is :-

−  

11

28

​  

+2=  

11

−28+22

​  

=−  

11

6

​  

 

So, the fraction is  

−  

11

6

​  

 

−  

11

28

​  

 

​  

=  

6

28

​  

=  

3

14

​  

 

Now adding 1 on both numerator and denominator we get  

4

15

​  

 

But,  

3

14

​  

+  

4

15

​  

 

=  

15

19

​  

 

∴x=3 and denominator is x+2=3+2=5

∴ the fraction is  

5

3

​  

 

Let the numerator be x

Therefore, denominator is x+2

The fraction is  

x+2

x

​  

 

Now,    

x+2

x

​  

+  

x+3

x+1

​  

=  

15

19

​  

 

=>  

(x+2)(x+3)

x  

2

+3x+(x+1)(x+2)

​  

=  

15

19

​  

 

=>  

(x+2)(x+3)

x  

2

+3x+x  

2

+3x+2

​  

=  

15

19

​  

 

=>15(x  

2

+3x+x  

2

+3x+2)=19(x+2)(x+3)

=>15(2x  

2

+6x+2)=19(x  

2

+5x+6)

=>30x  

2

+90x+30=19x  

2

+95x+114

=>11x  

2

−5x−84=0

=>11x  

2

−33x+28x−84=0

=>11x(x−3)+28(x−3)=0

=>(11x+28)(x−3)=0

Therefore, x=3 or x=−  

11

28

​  

 

For x=−  

11

28

​  

, denominator is :-

−  

11

28

​  

+2=  

11

−28+22

​  

=−  

11

6

​  

 

So, the fraction is  

−  

11

6

​  

 

−  

11

28

​  

 

​  

=  

6

28

​  

=  

3

14

​  

 

Now adding 1 on both numerator and denominator we get  

4

15

​  

 

But,  

3

14

​  

+  

4

15

​  

 

=  

15

19

​  

 

∴x=3 and denominator is x+2=3+2=5

∴ the fraction is  

5

3

​  

 

Let the numerator be x

Therefore, denominator is x+2

The fraction is  

x+2

x

​  

 

Now,    

x+2

x

​  

+  

x+3

x+1

​  

=  

15

19

​  

 

=>  

(x+2)(x+3)

x  

2

+3x+(x+1)(x+2)

​  

=  

15

19

​  

 

=>  

(x+2)(x+3)

x  

2

+3x+x  

2

+3x+2

​  

=  

15

19

​  

 

=>15(x  

2

+3x+x  

2

+3x+2)=19(x+2)(x+3)

=>15(2x  

2

+6x+2)=19(x  

2

+5x+6)

=>30x  

2

+90x+30=19x  

2

+95x+114

=>11x  

2

−5x−84=0

=>11x  

2

−33x+28x−84=0

=>11x(x−3)+28(x−3)=0

=>(11x+28)(x−3)=0

Therefore, x=3 or x=−  

11

28

​  

 

For x=−  

11

28

​  

, denominator is :-

−  

11

28

​  

+2=  

11

−28+22

​  

=−  

11

6

​  

 

So, the fraction is  

−  

11

6

​  

 

−  

11

28

​  

 

​  

=  

6

28

​  

=  

3

14

​  

 

Now adding 1 on both numerator and denominator we get  

4

15

​  

 

But,  

3

14

​  

+  

4

15

​  

 

=  

15

19

​  

 

∴x=3 and denominator is x+2=3+2=5

∴ the fraction is  

5

3

​ plz mark as brainliest 

 

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