Question

The numerator of a fraction is smaller than its denominator by four if the numerator is increased by three and I denominator is decreased by five the number becomes two find the fraction

Answer 1

Answer:

Fraction is :-

$\frac{5}{9}$

Step-by-step explanation:

Let the denominator be x.

Numerator = Denominator -4

= x - 4

Fraction =

$\frac{x - 4}{x}$

When Numerator is increased by 3, it will become = (x - 4) + 3

= x - 4 + 3

= x - 1

When denominator is decreased by 5, it will become = x - 5

According to question,

$\frac{x - 1}{x - 5} = 2$

On cross multiplying we get,

$2 (x - 5) = x - 1$

$2x - 10 = x - 1$

$2x - x = - 1 + 10$

$x = 9$

Denominator of the original fraction = x = 9

Numerator of the original fraction = x - 4

= 9 - 4

= 5

Hence, the original fraction is

$\frac{5}{9}$

Hope it helps!!!

Answer 2

Answer:

Fraction is :-

\frac{5}{9}

9

5

Step-by-step explanation:

Let the denominator be x.

Numerator = Denominator -4

= x - 4

Fraction =

\frac{x - 4}{x}

x

x−4

When Numerator is increased by 3, it will become = (x - 4) + 3

= x - 4 + 3

= x - 1

When denominator is decreased by 5, it will become = x - 5

According to question,

\frac{x - 1}{x - 5} = 2

x−5

x−1

=2

On cross multiplying we get,

2 (x - 5) = x - 12(x−5)=x−1

2x - 10 = x - 12x−10=x−1

2x - x = - 1 + 102x−x=−1+10

x = 9x=9

Denominator of the original fraction = x = 9

Numerator of the original fraction = x - 4

= 9 - 4

= 5

Hence, the original fraction is

\frac{5}{9}

9

5

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