Question

The numerator of a rational no. Is 8 less than its denominator .if the numerator is increased by 2 and denominator is decreased by 1 ,the no. Obtained is 1/2 . Find the numbers

Answer 1

Answer:

$Now, \red { The \: fraction} = \green {\frac{3}{11}}$

Step-by-step explanation:

$Let \: the \: denominator = x$

$Numerator = x-8$

$Now, \blue { The \: fraction = \frac{x-8}{x}}$

/* According to the problem given

if the numerator is increased by 2 and denominator is decreased by 1 ,,the no. Obtained is 1/2

$\pink { \frac{x-8+2}{x-1}=\frac{1}{2}}$

$\implies \frac{x-6}{x-1}=\frac{1}{2}$

$\implies 2(x-6) = x-1$

$\implies 2x - 12 = x - 1$

$\implies 2x - x = -1 + 12$

$\implies x = 11$

$The \: denominator = x = 11$

$Numerator = x-8 = 11-8 = 3$

Therefore.,

$Now, \red { The \: fraction} = \green {\frac{3}{11}}$

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Answer 2

Answer:

the numerator of rational number 8 is