Question

the numerator of a rational no. is less than its denominator by 3.If the numerator becomes three times and the denominator is incresed by 20,the new number becomes1/8.Find the original number​

Answer 1

Here's your solution buddy

Answer 2

Let the denominator be ' x '

The numerator will be ' x - 3 ' .

Therefore ,,,, the original fraction is :

$\frac{ x - 3}{x}$

According to the question ,,,

$= > \: \: \frac{3(x - 3)}{x + 20} = \frac{1}{8} \\ \\ \frac{3x - 9}{x + 20} = \frac{1}{8} \\ \\ 8(3x - 9) = x + 20 \\ \\ 24x - 72 = x + 20 \\ \\ 23x = 92 \\ \\ x = 4$

$= > \: \: x - 3 = 4 - 3 = 1$

Hence,,

the original fraction is

$\frac{1}{4}$

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