Question

The numerator of a rational number is 4 less than its denominator. If 1 is added to both its

numerator and denominator, it becomes ⅔



. Find the original rational number.​

Answer 1

Answer:

denominator = x

numerator = x-4

$\frac{x-4}{x} \\\frac{x-4+1}{x+1}=\frac{2}{3} \\\frac{x-3}{x+1} =\frac{2}{3} \\3(x-3) = 2(x+1)\\3x-9=2x+2\\3x-2x=2+9\\x=11$

DENOMINATOR IS 11

NUMERATOR IS 11-4=7

FRACTION IS 7/11

Answer 2

Answer:

-3/25

Step-by-step explanation:

Let the denominator of the rational no. be x.

Then, numerator (n)=x−4

Add 1 to both numerator and denominator,

Denominator = x+1 and Numerator =x−4+1=x−3

⟹ x+1/x−3

= 8/1

⟹8x−24=x+1

⟹7x=25

x= 25/7

Numerator = 25/7 −4 = 25−28 / 7

= -3/7

Rational number = −3/7 × 7/25

= −3/25