the numerator of a rational numer is 5 less than the denominator. if the denominator increase by 7 and numerator by 2. we again get the same rational number. find the number
nitin6999:
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Answered by
2
let denominator be x
and numerator be x -5
A/Q
X+2/X-5+7=x/x-5
X+2/X+2=x/x-5
(x+2)(x-5)=x(x+2)
x^2-3x-10=x^2+2x
-3x-10=2X
-10=2x+3x
-10=5x
-10/5=x
-2=×
numerator =-7
denominator=-2
and numerator be x -5
A/Q
X+2/X-5+7=x/x-5
X+2/X+2=x/x-5
(x+2)(x-5)=x(x+2)
x^2-3x-10=x^2+2x
-3x-10=2X
-10=2x+3x
-10=5x
-10/5=x
-2=×
numerator =-7
denominator=-2
Answered by
1
rational number 2/7
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