Question

the numerator of fraction is 1 less than its denominator .If one is added to both numerator and denominator . The fraction becomes 7\8 . find the fraction​

Answer 1

Step-by-step explanation:

given: numerator is 1 less than denominator

so, let: denominator= x

then, numerator= x-1

the fraction= x-1/x

now, 1 is added to both numerator and denominator..

then, x-1+1/x+1= x/x+1

so, x/x+1= 7/8 (given)

by solving above equation...

x/x+1= 7/8

by cross multiplying...

8(x)= 7(x+1)

8x= 7x+7

so, 8x-7x=7

therefore, x= 7

so, fraction= x-1/x= 7-1/7= 6/7

so, fraction= 6/7

hope it helps you!

Answer 2

Let the denominator of the fraction be x.

$\frac{x - 1}{x}$

Then 1 should be added to the fraction.

$\frac{x - 1 + 1}{x + 1} = \frac{7}{8}$

Cancel -1 and +1 in the numerator.

$\frac{x}{x + 1} = \frac{7}{8}$

$\frac{x}{x} = \frac{7}{8} - 1 \\ \\ \frac{x}{x} = \frac{7}{8} - \frac{8}{8} \\ \frac{x}{x} = \frac{ - 1}{8}$

Now as Numerator is 1 less than x , we have to:

$\frac{ - 1 - 1}{8} = \frac{ - 2}{8}$

Note: Not very sure about the answer.