Question

the numerator of fraction is 3 less than it's denometar if numerator is increased by 1and the denomerator is increased by 3 the fraction become 1/2 find the original number ​

Answer 1

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Answer 2

Let the denominator of the fraction be x.

According to the question the numerator is 3 less then the denominator .So,it will be x-3

After increasing the numerator by 1 the number will be (x-3) +1

After increasing the denominator by 3 The number in denominator will be x+3.

So, according to the question the equation will be

[(x-3)+1]/(x+3) =1/2

=>( x -3+1)/(x+3)=1/2

=>(x-2)/(x+3)=1/2

=>2(x-2)=1(x+3)

=>2x -4=x+3

=>2x -x= 3+4

x=7

Hence, numerator= [(x-3)+1]

=7-3=4

denominator=7

Hope this will help you!!!