Question

the numerator of fraction is 3 more than the denominator. if 1 is subtracted to both it becomes 3 by 4 find the fraction​

Answer 1

The statement of above question is wrong,

The statement should be,

the numerator of fraction is 3 more than the denominator. if 1 is subtracted to both it becomes 4 by 3 find the fraction​

In context to question asked,

We have to determine the value of fraction.

As per question,

It is given that,

The numerator of fraction is 3 more than the denominator.

Let the value of denominator of the fraction will be $=x$

So, the numerator of the fraction is x. $=(x+3)$

So, the fraction will be $\frac{x+3}{x}$

As, if 1 is subtracted from numerator and denominator it will become $\frac{4}{3}$.

So, value of numerator when 1 is subtracted from it will be $(x+3-1) = (x+2)$

Value of denominator when 1 is subtracted from it will be $=(x-1)$

So, value of new fraction will be $=\frac{x+2}{x-1}$

Hence, from above,

$\frac{x+2}{x-1} = \frac{4}{3}\\3(x+2) = 4(x-1)\\=>3x+6=4x-4\\=>4x-3x = 4+6\\=>x = 10$

So, value of the denominator will be 10.

So, value of the numerator will be $=(-10+3) = 13$

Hence, value of original fraction will be $\frac{13}{10}$.