The numerator of the fraction is 3 less than its denominator. If the denominator is increased by 5 and the numerator by 2 we get the fraction as find the fraction.
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Let The Value of The Denominator = x,
& Thus, The Numerator = x +5,
Let the Value of This Fraction, (x+5)/x = y, ….(1)
We are Given A fraction with Value of Denominator Increased by 5, such that:-
(x + 5)/(x + 5)=y - 5/4,
ie. y - 5/4 =1,
ie. 4y-5/4=1,
ie. 4y - 5=4, (cross -multiplying)
ie. 4y =5+4
ie. y =9/4 ….(2)
[This is the Sought Answer & Value Of The Equation & Our Answer ]
Even at this stage, We can see that Value Of Equation Makes Denominator Value 'x' =4, & Numerator Value as 'x + 5′ =9,
However, we will show it by Substituting the Value of y in Equation (2) in Equation (1) :-
(x +5)/x = 9/4,
4x + 20 =9x, (cross- multiplying),
ie. 9x - 4x =20,
ie. 5x =20,
ie. x =4 (Ans)
& our Fraction Becomes (4+5)/4 =9/4,
Hope it Helped
& Thus, The Numerator = x +5,
Let the Value of This Fraction, (x+5)/x = y, ….(1)
We are Given A fraction with Value of Denominator Increased by 5, such that:-
(x + 5)/(x + 5)=y - 5/4,
ie. y - 5/4 =1,
ie. 4y-5/4=1,
ie. 4y - 5=4, (cross -multiplying)
ie. 4y =5+4
ie. y =9/4 ….(2)
[This is the Sought Answer & Value Of The Equation & Our Answer ]
Even at this stage, We can see that Value Of Equation Makes Denominator Value 'x' =4, & Numerator Value as 'x + 5′ =9,
However, we will show it by Substituting the Value of y in Equation (2) in Equation (1) :-
(x +5)/x = 9/4,
4x + 20 =9x, (cross- multiplying),
ie. 9x - 4x =20,
ie. 5x =20,
ie. x =4 (Ans)
& our Fraction Becomes (4+5)/4 =9/4,
Hope it Helped
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