Question

the numerical coefficient of y in the expansion of (x-2y) ^3 ​

Answer 1

Answer:

$( {x - 2y})^{3} = {x}^{3} - 8 {y}^{3} - 6xy(x - 2y)$

$= > {x}^{3} - 8 {y}^{3} - 6 {x}^{2} y + 12x {y}^{2}$

$the \: numerical \: coefficient \: of \: y = 0$

${y}^{ 3} = - 8$