Question

the numerical difference of the roots of 2xsquare -7x-9=0 is

Answer 1

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Answer 2

$2{x}^{2} - 7x - 9 = 0 \\ 2 {x}^{2} + 2x - 9x - 9 = 0 \\ 2x(x + 1) - 9(x + 1) = 0 \\ (2x - 9)(x + 1) = 0 \\ x = - 1 \\ x = \frac{9}{2} \\ difference \: between \: roots \: = \frac{9}{2} + 1 \\ = \frac{11}{2}$
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