Question

the numerical value of 10m/s^2 in a system of units having unit of leangth as 10m and unit of time as 1/2s

Answer 1

As we know that

1 joule = 1kg*(m/s)^2

If

Unit of mass =10kg

Unit of length=10m

Unit of time =1 minut =60sec

Then

1 joule=10kg*(10m/60sec)^2

1 joule=10/36kg*(m/sec)^2

Then finally

1joule=0.277kg*(m/sec)^2

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Abhinav Rai, studied at Kendriya Vidyalaya BHU

Answered Sep 2

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Answer:

1 New Joule = 0.27 J

Explanation:

Joule is a derivative unity of measure whose value is:

1 J=1 Kg×1 m^2×1 s^−2

so if you put the new units you have

1 New Joule=10 kg×(10 m)2×(60 s)−1=10003600 J=0.27 J.

OR

Energy = Power×Time

= work done

= F×S

= m×a×S

= m×(S/t²)×S

= m×S²/t²

1 J = 1 kg × 1 m²/1 sec²

Now, in new system of units

S = 10m

m = 10 Kg

t = 1 min = 60 sec

Energy = m×S²/t²

= 10×100/3600

= 10/36

= 0.27

Hence in the new system the numerical value of 1 J will be 0.27

Hope, this helps you.

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Chitresh Khadoliya, former Relationship manager at Just Dial (2017-2018)

Answered Apr 2

1 joule = kg-m^2/s^2

Joule = [ML^2S^-2]

then further we solve this equation:

1 joule =10×(10×10)÷(60×60)

1 joule =1000÷3600

1 joule =0.27 Nm

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Pankaj Sharma, former Founder

Answered May 12

joule is basically used for energy in SI system

And 1 joule = mass x length ^2 / time ^2

So 1 joule = 10 x 100 / 60 x 60

1 joule = 10/36 kg m^2 / s^2

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Kushal Bhanot

Answered Jun 4

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A2A

Using dimensional analysis for this problem,

Work=Force∗DisplacementWork=Force∗Displacement

This implies, [work]=[ML2T−2][work]=[ML2T−2]

Therefore, 1Joule=(10kg)∗(10m)2∗(60s)−21Joule=(10kg)∗(10m)2∗(60s)−2

{It is important to note the conversion of time into seconds because Joule is a standard unit but ‘minute’ is not.}

1Joule=5/18kgm2s−21Joule=5/18kgm2s−2

Hope it answers your question.

-KB

912 Views · Answer requested by Somnath Mahabale

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Sudip Nath, A.M.I.E Electronics & Communication, IEI Kolkata (2008)

Answered May 10

1 Joule is 1 Newton metre so 1kgf should be converted into 9.8m/s^2 which is the acceleration multiplied by 10 since 1kg is represented by 10 kg change other units like length and time by the data provided