Question

The numerical value of side of a cube of volume 64 cm' is the zero of 2x'+5x+ k ,then k=
A 36
B) - 36
C) - 52
D 41​

Answer 1

Answer:

6ryryryyr66y the same to you

Answer 2

Answer:

Given,

numerical value of side of a cube of volume is zero of 2x^2+5x+k

given volume=64cm3

then,a=4

hence 4 is one of the zero of polynomial

substitute 4 in the polynomial

then,

2(4^2)+5(4)+k=0

2(16)+20+k=0

32+20+k=0

52+k=0

k=-52

--------