Math, asked by preethitrapthi1234, 8 months ago

the numerical value of side of a cube of volume 64cm 3 is the zero of 2x²+5x+k, then =​

Answers

Answered by saranyamadaapms
2

Answer:

k=-52

Step-by-step explanation:

volume of cube is a^3,

a^3=64

a^3=4^3

a=4

2x^2+5x+k=0

2(4)^2+5(4)+k=0

2(16)+20+k=0

32+20+k=0

52+k=0

k=-52

Answered by Swarup1998
0

Given data:

The numerical value of a side of a cube of volume 64\:cm^{3} is the zero of 2x^{2}+5x+k

To find:

The value of k

Step-by-step explanation:

Given, the volume of the cube is 64\:cm^{3}

Then the length of a side of it

=\sqrt[3]{64}\:cm

=\sqrt[3]{4^{3}}\:cm

=4\:cm

Given that the numerical value of 4\:cm, that is, 4 is a zero of 2x^{2}+5x+k, then

\quad 2(4^{2})+5(4)+k=0

\Rightarrow 32+20+k=0

\Rightarrow k=-52

Final answer:

The value of k is (-52).

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