Question

the numerical value of tan20° tan 80° cot 50° is equal to​

Answer 1

Answer:

Correct option is

A

3

tan20tan80cot50

=

tan(60−10)

tan(30−10)tan(90−10)

=

1+tan60tan10

tan60−tan10

1+tan30tan10

tan30−tan10

cot10

=

tan10

1+

3

tan10

3

−tan10

1+

3

1

tan10

3

1

−tan10

=

tan10⋅

1+

3

tan10

3

−tan10

3

+tan10

1−

3

tan10

=

tan10(3−tan

2

10)

1−3tan

2

10

=

3tan10−tan

3

10

1−3tan

2

10

=

tan3(10)

1

=

tan30

1

=

3

Step-by-step explanation:

i hope this helps you