Question

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The numerical value of tan3º+tan42º+tan3ºtan42°​

Answer 1

Answer:

1=tan3°+tan42°+tan3°tan42°

Step-by-step explanation:

tan(45°) =tan3°+tan42°

________________

1-tan3°tan42°

1=tan3°+tan42°

= ________________

1-tan3°tan42

= 1=tan3°tan42°=tan3°+tan42°

=. 1=tan3°+tan42°+tan3° tan42°

Hence proved !