Question

The numerical value of whole surface and volume of a cube are equal. Find sum of length of its diagonals.

Answer 1

Step-by-step explanation:

Let the edge length be [math]'a'.[/math]

Total number of edges in a cube = 12

Length of all the edges (L) = [math]12a[/math]

Volume of the cube (V) =[math]a^3[/math]

Given, V=L

[math]a^3=12a[/math]

[math]a^3-12a=0[/math]

[math]a(a^2-12)=0, a≠0[/math] (if a=0 then cube will reduce to a point which is not possible.)

[math]a^2=12[/math]

A cube has 6 square shaped faces with area of each face = [math]a^2[/math]

Total surface area = [math]6a^2 =6*12=72unit^2[/math]

Answer 2

Answer:

Let each edge of the cube = x units.Then, x3 = 12x x2 = 12 Total surface area of the cube = 6 (x)2 = 6x2 = 6 × 12 = 72 units

$\beta \beta \gamma \alpha e\pi \infty ln( log(?) )$