Math, asked by chintukhanke7301, 5 months ago

The numerical value of [x^1/a-b]^1/a-c × [x^1/b-c]^1/b-a × [x^1/c-a]^1/c-b is : (Step by step)

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Answered by sachinjanuary16

0

Answer:

The numerical value of [x^1/ a-b]^1/a-c × [x^1/b-c]^1/b-a × [x^1/c-a]^1/c-b is : (Step by step) - 22039722.

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