Math, asked by swarishreddy01, 1 month ago

The numerical values of the area and perimeter of a square field are in the ratio 7:4, while that of a square park are in the ratio 5:1. Which of these has a greater side length?​

Answers

Answered by ExoticStar
57

Hi good morning im fine

How are you ?

HERE IS UR ANSWER

1) Given:-

The numerical values of the area and perimeter

of a :-

  • Square Field = 7: 4
  • Square Park = 5: 1

2) To find :-

  • Which of these has a greater side length ?

3) Formulas used :-

  • Perimeter = 4a
  • Area = a²

4) Solution :-

  • Let the side of square Field be = x unit

5) Hence,

  • Area of field = x²
  • Perimeter of field = 4x

6) According to the given condition :-

  • Area/ Perimeter = 7/4
  • x²/4x =7/4

(Here ² , 4x and 4 will get cancelled )

  • x = 7

Hence side length of the field =4 unit

  • Let the side length of Square Park be = y unit

7) Hence,

  • Area of field = y²
  • Perimeter of field = 4y

8) According to the given condition :-

  • Area/Perimeter = 5/1
  • y²/4y = 5/1

( Here ² and y gets cancelled )

  • y=20

Hence side length of field=20unit

FROM BOTH WE CLEARLY GET :-

Side length of Square Park is greater than the side length of Square field .

HOPE IT HELPS U

Answered by Anonymous
5

Given :-

  • The numerical values of the area and perimeter of a square field are in the ratio 7:4, while that of a square park are in the ratio 5:1.

To Find :-

  • Which of these has a greater side length?

Solution :-

For field

Let the side of square field be a

\longrightarrowPerimeter = 4 × side

\longrightarrowPerimeter = 4 × a

\longrightarrowPerimeter = 4a

Area = side × side

Area = a × a

Area = a²

\impliesArea/Perimeter = 7/4

\longrightarrowa²/4a = 7/4

\longrightarrow4 × (a²) = 7(4a)

\longrightarrow4a² = 28a

\longrightarrow4 × a × a = 28 × a

\longrightarrow4a = 28

\longrightarrowa = 28/4

\longrightarrowa = 7

For park

Let the side of park be b

\longrightarrowPerimeter = 4 × side

\longrightarrowPerimeter = 4 × b

\longrightarrowPerimeter = 4b

\impliesArea = side × side

\longrightarrowArea = b × b

\longrightarrowArea = b²

Area/Perimeter = 5/1

\longrightarrowb²/4b = 5/1

\longrightarrow1(b²) = 5(4b)

\longrightarrowb² = 20b

\longrightarrowb × b = 20 × b

\longrightarrowb = 20

Hence,

Square park has greater side

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