Question

the nunber of possible pairs of number, whose product is 5400 and the h.c.f is 30 is

Answer 1

Solution:-

given product is = 5400

hcf = 30

= 5400/30 = 180 = (30,180)

= 5400/60 = 90 = ( 60, 90)

= 5400/45 = 120 = (45 , 120)

= 54400/90 = 60 = ( 60,90)

there are two right pair posisible (30,18)ans (60, 90)

your right answer is (two )pairs possible

Answer 2

Answer:

Two numbers of pairs are possible whose product is 5400 and H.C.F is 30.

Step-by-step explanation:

To find : The number of possible pairs of number, whose product is 5400 and the H.C.F is 30 ?

Solution :

H.C.F of number is 30.

So, required numbers should be multiple of 30.

Lets the number are 30a and 30b.

Thew product of numbers = 5400

So, $30a\times 30b=5400$

$900ab=5400$

$ab=\frac{5400}{900}$

$ab=6$

The co-primes or possible pairs of product 6 either (1,6) and (2,3), or (6,1) and (3,2).

i.e. $ab=6$

$30a\times 30b=5400$

(1,6) a=1 and b=6

$30\times 180=(30,180)=5400$

(2,3) a=2 and b=3

$60\times 90=(60,90)=5400$

Thus, two numbers of pairs are possible whose product is 5400 and H.C.F is 30.