The O.N. of nitrogen in NO₃⁻ is
(a) – 1 (b) + 2
(c) + 3 (d) + 5
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(d) + 5
Explanation:
The Oxidation Number of nitrogen in NO₃⁻ is as follows:
The oxidation number of oxygen is -2 and the charge of the ion is given as -1. So we get:
-2*3 + x = -1
-6 + x = -1
x = +5
Option D is the answer.
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