Chemistry, asked by gurnoor2644, 11 months ago

The O.N. of nitrogen in NO₃⁻ is
(a) – 1 (b) + 2
(c) + 3 (d) + 5

Answers

Answered by topwriters
0

(d) + 5

Explanation:

The Oxidation Number of nitrogen in NO₃⁻ is as follows:

The oxidation  number of oxygen is -2 and the charge of the ion is given as -1. So we get:

-2*3 + x = -1

-6 + x = -1

 x = +5

Option D is the answer.

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