the object distance of a lens is -30 cm and the image distance is -10 cm find the magnification of the lens with the help of this decide whether the size of the image is smaller or bigger than the size of the object
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Magnification= h2/h1
=-10/-30
= 1/3
As magnification is +ve and in 'p/q' form the size of the image will obviously be smaller than the object!.....
mark me as the brainliest!....
Answered by
2
We will conclude that it is a concave lens since u=-30 and v=-10 so we can confirm it by the lens formula which will give us =-15cm focal length which means that the img is virtual and erect we can find magnification m=+3 which means virtual and erect img the size of the img will be 3 times the obj mark me brainliest
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