Physics, asked by amandavbhagalpur1968, 5 months ago


The object dropped from a height (h) with initial velocity zero strikes the ground with a velocity of 30m's.
How long does it take to reach the ground. Also find h lg = 10m/s)​

Answers

Answered by AestheticSoul
56

Given -

  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 30 m/s
  • Acceleration due to gravity (g) = \sf{10~m/s^2}

To find -

  • Time the object will take to reach the ground.
  • Height.

Solution -

  • v = u + at

Substitute the given values -

30 = 0 + 10 × t

30 = 10 × t

\sf{\dfrac{30}{10}} = t

t = 3s

\overbrace{\underbrace{\sf{\red{Time = 3~seconds}}}}

  • \sf{v^2 - u^2 = 2as}

Substitute the given values.

\sf{(30)^2 - (0)^2 = 2 \times 10 \times s}

\sf{900 = 20 \times s}

\sf{\dfrac{900}{20} = s}

s = 45 m

\overbrace{\underbrace{\sf{\red{Height = 45~m}}}}

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Know more -

Velocity -

  • It is distance travelled by a body in one second in a particular direction.
  • It is a vector quantity.
  • Its S.I. unit is m/s.

Acceleration -

  • It is the rate of change of velocity of a body.
  • It is vector quantity.
  • Its S.I. unit is \sf{m/s^2}

Equations of motion -

First equation of motion -

  • v = u + at

Second equation of motion -

  • s = ut + \sf{\dfrac{1}{2} at^2}

Third equation of motion -

  • \sf{v^2 - u^2 = 2as}

where,

v = Finial velocity

u = Initial velocity

a = acceleration

s = distance/displacement

t = time

Answered by Blossomfairy
38

Given :

  • Initial velocity, u = 0 m/s
  • Final velocity, v = 30 m/s
  • Acceleration due to gravity, g = 10 m/s

To find :

  • Time taken to reach the ground (t)
  • Height (h)

According to the question,

Note : Here,

  • Acceleration (a) = Acceleration due to gravity (g)

v = u + at

Where,

  • v = Final velocity
  • u = Initial velocity
  • a = Acceleration
  • t = Time

→ Substituting the values,

→ 30 = 0 + 10 × t

→ 30 - 0 = 10t

→ 30 = 10t

→ 30 ÷ 10 = t

→ 3 = t

So,the time is 3 seconds.

Now,

v² = + 2as

Where,

  • v = Final velocity
  • u = Initial velocity
  • a = Acceleration
  • s = Distance

→ Substituting the values,

→ (30)² = (0)² + 2 × 10 × s

→ 900 = 0 + 20s

→ 900 - 0 = 20s

→ 900 = 20s

→ 900 ÷ 20 = s

→ 45 = s

So,the height is 45 metres.

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