The object is 1.5m forms on a mirror which formed an errect image one-fourth[exactly the same size of the object determine the focal length of the mirror what type of mirror is it
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u=−2m
m=+
4
1
(Erect image)
m=
u
v
4
1
=
−2
v
v=−0.5m
v
1
−
u
1
=
f
1
−0.5
1
−
−2
1
=
f
1
f=−0.666m=−66.6cm
It is a convex lens.
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