Question

the object is kept at a distance of 15cm from a curved mirror of focal length 10cm which always produces virtual image, the position of the image is ​

Answer 1

Answer:-

• Object distance=u=-15cm
• Focal length=f=10cm
• Image distance=v=?

According to mirror formula

$\boxed{\sf \dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}}$

$\\ \sf\longmapsto \dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}$

$\\ \sf\longmapsto \dfrac{1}{v}=\dfrac{1}{10}-\dfrac{1}{-15}$

$\\ \sf\longmapsto \dfrac{1}{v}=\dfrac{1}{10}-\dfrac{1}{15}$

$\\ \sf\longmapsto \dfrac{1}{v}=\dfrac{3-2}{30}$

$\\ \sf\longmapsto \dfrac{1}{v}=\dfrac{1}{30}$

$\\ \sf\longmapsto v=30cm$