the object is placed at right angle to the principal axis of concave mirror at the distance of 30cm from the pole the image formed is real and twice the size of the object find another postion of the object so that tge size of the image will be again twice the object
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Answered by
5
Answer:
Answer
Given,
Focal length, f=−30 cm if u=−x
real ⇒ same side ⇒v=−ve
Magnification, m=
u
v
⇒v=m×u=3×(−x)=−3x
From mirror formula,
f
1
=
v
1
+
u
1
We get
−30
1
=
−3x
1
+
−x
1
⇒
30
1
=
3x
1+3
⇒
4
3x
=3⇒x=40 cm
So object should be placed at 40 cm to the mirror.
Answered by
0
Answer:
Objects should be placed 40 cm to the mirror.
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