Question

The object is therown ventically upward and rises to a height of 10m. . Calculate
1The velocity with which the object was thrown upward
2) The time taken by the object to reach the highest point.​

Answer 1

Put third equation of motion,take a=-10si.unit

0^2=u^2-2*10*10

u^2=200

u=√200

initial velocity is approximately

14.14m/s

now time,

v=u+at

0=10√2-10*t

10√2=10t

we have,

t=√2

time is approximately,

1.41s

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