Question

The object of m force moves along the x-axis. At any point t is given by the location x = at ^ 4-bt ^ 3 + ct. where a, b, c are constants. So the force exerted on it at time t?​

Answer 1

Explanation:

Here the equation for x is given .

so differentiate it for the first time to get the velocity .

you will get = 4at^3-3bt^2+c

then differentiate it for the second time . which will give you the acceleration . you will get

a= 12at^2-6bt

now at time t

F = 12amt^2-6mbt