The object of mass 3kg, 5kg. 6kg, and 2 kg are placed at the vertices A.
B. C and D of a square length 1 m. Then moment of inertia with respect to
axis perpendicular to its plane and passing through it centre is
(A) 6 kg m-
(B) 8 kg m-
(C) 4 kg m
(D) 16 kg m-
along its axis with 30 rpm. To incerase its angular
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Answer:
To find centre of mass
X
COM
=∑
i=1
4
x
1
M
1
X
COM
=
M
4
+M
2
+M
3
+M
4
M
i
x
i
+M
2
x
2
+M
3
x
3
+M
4
x
4
=
10
0+0+3+4
=
10
7
Y
COM
=∑
i=1
4
Y
i
M
i
=
10
0+2+3+0
=
10
5
=
2
1
(
10
7
,
2
1
)=COM
solution
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