Question

The odds against a person hitting a target all 2 to 7. If if he fires twice at a target what is the probability that the target is hit

Answer 1

Hey Dear,

◆ Answer -

P = 4/49

◆ Explanation -

The probability of of the person hitting target both times when he hit it is calculated by -

P = 2/7 × 2/7

P = 4/49

Therefore, the probability of person hitting the target accurately both times he fired is 4/49.

* If you want to know probability of hitting at least one target, that's 24/49.

Thanks...

Answer 2

The required probability is $\dfrac{4}{81}$

Step-by-step explanation:

Since we have given that

Odds against a person hitting a target = 2:7

So, it becomes,

$\dfrac{2}{7}=\dfrac{P(A)}{1-P(A)}\\\\2(1-P(A))=7P(A)\\\\2-2P(A)=7P(A)\\\\2=7P(A)+2P(A)\\\\2=9P(A)\\\\P(A)=\dfrac{2}{9}$

Since it fires twice,

So, Probability that the target is hit is given by

$\dfrac{2}{9}\times \dfrac{2}{9}=\dfrac{4}{81}$

Hence, the required probability is $\dfrac{4}{81}$

# learn more:

The odd's against a person hitting a target all 227 if he fires twice at the target what is the probability that the target is hit?

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